V(50v^2-18)=0

Solution for V(50v^2-18)=0 equation:

(50V^2-18)=0

We get rid of parentheses

50V^2-18=0

a = 50; b = 0; c = -18;
Δ = b2-4ac
Δ = 02-4·50·(-18)
Δ = 3600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$V_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$V_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3600}=60$
$V_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-60}{2*50}=\frac{-60}{100}
=-3/5
$
$V_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+60}{2*50}=\frac{60}{100}
=3/5
$